20y^2-37y-18=0

Solution for 20y^2-37y-18=0 equation:

20y^2-37y-18=0

a = 20; b = -37; c = -18;
Δ = b2-4ac
Δ = -372-4·20·(-18)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-53}{2*20}=\frac{-16}{40}
=-2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+53}{2*20}=\frac{90}{40}
=2+1/4
$